Question

In the circuit shown in figure, a conducting wire $HE$ is moved with a constant speed $v$ toward left. The complete circuit is placed in a uniform magnetic field $\overrightarrow{B}$ perpendicular to the plane of the circuit inward. The current in $HKDE$ is

• A. clockwise
• B. anticloclwise
• C. alternating
• D. zero
• E. answer required

Answer 1

Answer: (D)

zero

Assuming the $AK$ and $BD$ are infinitely long
By Faraday's Law
$E=\frac{d\varphi }{dt}=BvL$
$E_{HE}=BvL$
The analogous diagram is shown in the figure below
Resistor and capacitor are in parallel
$E-V_c=0$
$V_C=Bvl$
and
$Q=CV=CE=const$
$i_C=\frac{dQ}{dt}=0$