Question

In the circuit shown in figure $C_1=C_2=C$ and capacitor $C_1$ having initial charge $Q$, the switch is closed at $t=0$. Then _______

• A. Total heat loss in the circuit till the current becomes zero is $\frac{Q^2}{4C}$
• B. Total heat loss in the circuit till the current becomes zero is $\frac{Q^2}{2C}$
• C. The current at time $t$ in the circuit will be ${\left(\frac{R}{QC}\right)}^{}{e}^{-2t/RC}$
• D. Charge on capacitor $C_1$ at time $t$ will be $\frac{Q}{2}(1+e^{-2t/RC})$

Answer 1

The correct option is A Total heat loss in the circuit till the current becomes zero is $\frac{Q^2}{4C}$