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Question

In the circuit shown in figure, C1=C2. Then charge stored in
1078523_278d4048ec7c4742bf23c4944c950c45.png

A
Capacitor C1 is zero
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B
Capacitor C2 is zero
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C
Both capacitor is zero
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D
Capacitor C1 is 40μC
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Solution

The correct options are
B Capacitor C2 is zero
D Capacitor C1 is 40μC
i=120Req=120(12+12)1=40A

Now, this i will be divided equally, so i1=20A and i2=20A

Now, ΔV2=0

and

QC1=20×2μC=40μC


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