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Question

In the circuit shown in Figure charge on 1μF and 3μF capacitors respectively is :

144469_8ee45b89ff0b456fb202130a13c88b99.png

A
7μC,3μC
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B
3μC,3μC
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C
7μC,21μC
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D
3μC,21μC
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Solution

The correct option is D 3μC,21μC
I=VR
i1=93+6=1A
i2=92+7=1A
Potential difference at 3Ω
= Potential difference at 1μF
1×3=3V
Charges at 1μF=CV=1×3=3μC
Similarly
Potential difference at 3μF=Potential difference at 7Ω =i2×7=1×7=7V
Charge at 3μF=CV=3×7=21μC

951826_144469_ans_564e59135df649e0b6c48745142f8e27.png

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