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Byju's Answer
Standard XII
Physics
Kirchoff's Voltage Law
In the circui...
Question
In the circuit shown in figure. Current through
R
2
is zero if
R
4
=
2
Ω
and
R
3
=
4
Ω
.
In this case:
A
current through
R
3
is 2A
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B
current through
R
4
is 3A
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C
both (1) and (2) are correct
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D
both (1) and (2) are wrong
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Solution
The correct option is
D
both (1) and (2) are wrong
Correct answer: A current through
R
3
=
2.5
A
Apply Kirchhoff's law
for left loop,
(
R
1
+
R
3
)
i
1
+
R
2
(
i
1
−
i
2
)
R
2
=
15
+
10
=
25
as no current flow through
R
2
so
i
1
−
i
2
=
0
⇒
i
1
=
i
2
thus,
(
R
1
+
R
3
)
i
1
=
25
.
.
.
(
1
)
for right loop,
R
2
(
i
2
−
i
1
)
+
R
4
i
2
=
−
5
or
R
4
i
1
=
−
5
as
(
i
1
=
i
2
)
or
i
1
=
−
5
R
4
=
(
−
5
/
2
)
A
Thus, the current through
R
3
and
R
4
are equal and the magnitude of the current is
(
5
/
2
)
A
Suggest Corrections
0
Similar questions
Q.
In the circuit shown in figure. For what ratio
R
2
R
4
current through
R
3
will be zero ?
Q.
In the given circuit, the current through branch having indicated resistor
R
4
is
375
×
10
−
x
A
. Find x.
Given
R
1
=
R
2
=
4
Ω
,
R
3
=
R
4
=
R
5
=
2
Ω
,
ε
1
=
5
V
,
ε
2
=
10
V
Q.
In the circuit shown if
R
1
:
R
2
:
R
3
:
R
4
=
1
:
2
:
3
:
4
then_____
Q.
In the given circuit,
E
1
=
3
V
,
E
2
=
2
V
,
E
3
=
6
V
,
R
1
=
2
Ω
,
R
4
=
6
Ω
,
R
3
=
2
Ω
,
R
2
=
4
Ω
,
C
=
5
μ
F
. The energy stored in the capacitor is :
Q.
In the circuit shown in figure,
R
1
=
R
2
=
R
3
=
R
Table 1
Table - 2
(a) current through
R
1
(p) E/R
(b) current through
R
2
(q) 2E/R
(c) current through
R
3
(r) E/2R
(s) Zero
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