1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Physics
Magnetic Field Due to a Straight Current Carrying Conductor
In the circui...
Question
In the circuit shown in figure
E
1
=
2
V
,
E
2
=
20
V
,
R
1
=
R
2
=
10
k
Ω
and
C
=
1
μ
F
. Find the current through
R
1
,
R
2
and C when
The switch is suddenly shifted to B.
Open in App
Solution
When switch is at
A
at steady state
V
c
=
E
1
2
=
1
V
When switch is at B suddenly In loop
1
I
2
R
2
=
V
c
=
1
V
I
2
=
1
R
2
=
10
−
4
A
=
0.01
m
A
In daughter loop
I
=
21
10
R
=
2.1
m
A
I
c
=
I
+
I
2
=
2.2
m
A
Suggest Corrections
0
Similar questions
Q.
In the circuit shown in figure
E
1
=
2
E
2
=
20
V
,
R
1
=
R
2
=
10
k
Ω
and
C
=
1
μ
F
. The sum of current through
R
1
,
R
2
and C when
S has been kept connected to A for a long time.
Q.
In the circuit shown in Figure,
E
1
=
E
2
=
E
3
=
2
V
and
R
1
=
R
2
=
4
Ω
. The current flowing between points
A
and
B
through battery
E
2
is
Q.
Two resistances
R
1
and
R
2
are joined as shown in the figure to two batteries of e.m.f.
E
1
and
E
2
. If
E
2
is short-circuited, the current through
R
1
is
Q.
In the circuit shown infigure,
E
1
=
E
2
=
E
3
=
2
V
and
R
1
=
R
2
=
4
R
. The current flowing between points
A
and
B
through
battery
E
2
is
Q.
In the circuit shown here
E
1
=
E
2
=
E
3
=
2
V
and
R
1
=
R
2
=
4
Ω
.
The current flowing between point A and B through battery
E
2
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Magnetism Due to Current
PHYSICS
Watch in App
Explore more
Magnetic Field Due to a Straight Current Carrying Conductor
Standard X Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app