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Simple Circuit

In the circui...

Question

In the circuit shown in figure, $E_{1} = E_{2} = E_{3} = 2 V$ and $R_{1} = R_{2} = 4 Ω$ . The current flowing between points $A$ and $B$ through battery $E_{2}$ is

A

zero

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B

2 A f r o m A t o B

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C

2 A f r o m B t o A

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D

none of the above

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Solution

The correct option is B $2 A f r o m A t o B$
Applying KVL ,
For loop (1), $2 + 2 = 4 I_{1}$ or $I_{1} = 1 A$
For loop (2), $- 2 - 2 = - 4 I_{2}$ or $I_{2} = 1 A$
Thus, $(I_{1} + I_{2}) = (1 + 1) = 2 A$ will flow from A to B.

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