In the circuit shown in Figure- E1- E2 - E3 - 2 V and R1 - R2 - 4- The current flowing between points A and B through battery E2 is

The correct option is B 2 A from A to B Applying KVL , nbsp;for loop (1), 2+2=4I_1 or I_1=1 nbsp;A for loop (2), nbsp; 2 ...

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Byju's Answer

Standard XII

Physics

Simple Circuit

In the circui...

Question

In the circuit shown in Figure, $E_{1} = E_{2} = E_{3} = 2 V$ and $R_{1} = R_{2} = 4 Ω$ . The current flowing between points $A$ and $B$ through battery $E_{2}$ is

zero

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2 A f r o m A t o B

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2 A f r o m B t o A

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none of the above

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Solution

The correct option is B $2 A f r o m A t o B$
Applying KVL ,
for loop (1), $2 + 2 = 4 I_{1}$ or $I_{1} = 1 A$
for loop (2), $- 2 - 2 = - 4 I_{2}$ or $I_{2} = 1 A$
Thus, $(I_{1} + I_{2}) = (1 + 1) = 2 A$ will flow from A to B.

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In the circuit shown in Figure, E1=E2=E3=2V and R1=R2=4Ω. The current flowing between points A and B through battery E2 is

The correct option is B 2AfromAtoBApplying KVL , for loop (1), 2+2=4I1 or I1=1Afor loop (2), −2−2=−4I2 or I2=1AThus, (I1+I2)=(1+1)=2A will flow from A to B.

In the circuit shown in Figure, $E_{1} = E_{2} = E_{3} = 2 V$ and $R_{1} = R_{2} = 4 Ω$ . The current flowing between points $A$ and $B$ through battery $E_{2}$ is

The correct option is B $2 A f r o m A t o B$
Applying KVL ,
for loop (1), $2 + 2 = 4 I_{1}$ or $I_{1} = 1 A$
for loop (2), $- 2 - 2 = - 4 I_{2}$ or $I_{2} = 1 A$
Thus, $(I_{1} + I_{2}) = (1 + 1) = 2 A$ will flow from A to B.