Question

In the circuit shown in figure, find the potentials of $A$,$B$, $C$ and $D$ and the current through 1$\Omega$ and 2$\Omega$ resistance.

Answer 1

Since A is grounded, potential at A, $V_a=0V$
Potential at B,
$V_b-V_a=2V{V}_b-0=2V{V}_b=2V$
Potential at C,
$V_c-V_a=5V{V}_c-0=5V{V}_c=5V$
Potential at D,
$V_d-V_c=10V{V}_d-5=5V{V}_d=15V$
Since, $V_c$ is greater than $V_b$ current will flow from C to B and the magnitude will be given by
Current through $1\Omega$ resistor = $\frac{V_{cb}}{1}=5-2=3A$
Since, $V_d$ is greater than $V_a$ current will flow from D to A and the magnitude will be given by
Current through $2\Omega$ resistor = $\frac{V_{da}}{2}=\frac{15-0}{2}=7.5A$