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Equivalent Resistance in Series Circuit

In the circui...

Question

In the circuit shown in figure, find the ratio of currents $i_{1} / i_{2}$

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Solution

Refer above image.
On simplifying the circuit
$i_{1} = 4 A$
$i_{2} = \frac{2}{4} A = \frac{1}{2} A$
$\frac{i_{1}}{i_{2}} = \frac{8}{1}$

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