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Question

In the circuit shown in figure, if C1=C2=2 μF ,then charges present on C1 and C2 will be


A
0,40 mC
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B
40 mC,0
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C
20 mC,10 mC
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D
30 mC,60 mC
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Solution

The correct option is B 40 mC,0
In steady state


I=VReff

From the given figure,

I=1203=40 A

VAVB=20×1=20 V; VAVE=20×2=40 V

(VAVE)(VAVB)=4020

VBVE=20 V

Charge on

Q1=C1 VBE=2×20=40 mC

VCVD=3×20=60 V

VFVD=20×3=60 V

VCVF=0 charge on C2 is zero.

Hence, option (b) is the correct answer.

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