In the circuit shown in figure- L-10H-R-5- E-15V- The switch S is closed at t-0- At t-2s- the current in the circuit is

The correct option is A 3( 1 1 e ) A Concepts attached τ = LR= 2s i_o = E/R = 3A for growth of currentthe governing equation is i = i_o (1 ...

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Byju's Answer

Standard XII

Physics

Electrical Oscillations

In the circui...

Question

In the circuit shown in figure, $L = 10 H, R = 5 Ω, E = 15 V$ . The switch $S$ is closed at $t = 0$ . At $t = 2 s$ , the current in the circuit is

3 (1 - \frac{1}{e}) A

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3 (1 - \frac{1}{e^{2}}) A

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3 (\frac{1}{e}) A

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3 (\frac{1}{e^{2}}) A

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Solution

The correct option is A $3 (1 - \frac{1}{e}) A$
Concepts attached
$τ = \frac{L}{R} = 2 s$
$i_{o} = E / R = 3 A$

for growth of current
the governing equation is
$i = i_{o} (1 - e^{- t / τ})$
put t= 2s
$i = 3 (1 - \frac{1}{e})$

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In the circuit shown in figure, L=10H,R=5Ω,E=15V. The switch S is closed at t=0. At t=2s, the current in the circuit is

The correct option is A 3(1−1e)AConcepts attachedτ=LR=2sio=E/R=3Afor growth of currentthe governing equation isi=io(1−e−t/τ)put t= 2si=3(1−1e)

In the circuit shown in figure, $L = 10 H, R = 5 Ω, E = 15 V$ . The switch $S$ is closed at $t = 0$ . At $t = 2 s$ , the current in the circuit is

The correct option is A $3 (1 - \frac{1}{e}) A$
Concepts attached
$τ = \frac{L}{R} = 2 s$
$i_{o} = E / R = 3 A$

for growth of current
the governing equation is
$i = i_{o} (1 - e^{- t / τ})$
put t= 2s
$i = 3 (1 - \frac{1}{e})$