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Electric Power

In the circui...

Question

In the circuit shown in figure, match the following two columns. In column $I I$ quantities are given in $S I$ units.

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Solution

(a) $R = \frac{V_{R}}{I} = \frac{40}{2} = 20 Ω$
(b) $V_{C} = I X_{C} = 2 \times 30 = 60 V$
(c) $V_{L} = I X_{L} = 2 \times 15$ =30V $(d)$ V=\displaystyle \sqrt{V^2_R+(V_C-V_L)^2}=50V$

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