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Question

In the circuit shown in figure, R = 10 Ω, L = 5H, E = 20 V, i = 2A. This current is decreasing at the rate of 1.0 Asec.

A
Vab=25 V
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B
Vab=35 V
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C
Ldidt = 5V
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D
L didt = -5V
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Solution

The correct options are
B Vab=35 V
D L didt = -5V
Ldidt=5×(1)=-5 Volt

Vab=E+iR+VL=20+(2×10)5 = 35 Volt

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