Question

In the circuit shown in figure switch S is closed at time t = 0. Let $i_1$ and $i_2$ be the currents at any finite time t then the ratio $\frac{i_1}{i_2}$

• A. Is constant
  
• B. Increases with time
  
• C. Decreases with time
  
• D. First increases and then decreases

Answer 1

Answer: (B), (C)

The correct options are
B Increases with time

C Decreases with time


$i_1=\frac{V}{R}{e}^{\frac{-t}{2CR}}$
and $i_2=\frac{V}{R}{e}^{\frac{-t}{CR}}$
$\therefore$ $\frac{i_1}{i_2}=e^{\frac{t}{2CR}}$
i.e., the desired ratio increases with time.