In the circuit shown in figure the current through
The equivalent resistance between points A and B to the right of AB is 4 ohm. Therefore total resistance =3+4+2= 9 ohm. Current I =99=1 A. This current is equally divided in the 8 ohm resistor between A and B and the remainder 8 ohm resistor. Hence current in AC =0.5 A. This current is equally divided between the 8 ohm resistor in CD and the circuit to the right of CD. Therefore current in the 4 ohm resistor = 0.25 A