Question

In the circuit shown in Figure, the magnitudes and the direction of the flow of current, respectively, would be :

• A. $\frac{7}{3}$ A from a to b via e
• B. $\frac{7}{3}$ A from b to a via e
• C. $1A$ from b to a via e
• D. $1A$ from a to b via e

Answer 1

The correct option is D $1A$ from a to b via e

$NetEmf=10V-4V=6V,Totalresistance=3+2+1=6\Omega$

hence $I=6/6=1A$
For the direction of current, we can see the $10V$ battery will over ride it's current from $4V$ battery so net emf is positive due to $10V$ battery is dominant over $4V$ battery. so current will flow from $10V$ battery from direction $a$ to $e$