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Mixed Combination of Cells

In the circui...

Question

In the circuit shown in figure, the reading of the ammeter is (assume internal resistance of the battery be to zero)

\frac{40}{29} A

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\frac{10}{9} A

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\frac{5}{3} A

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Solution

The correct option is A 2A
Voltage across $5 Ω$ resistance is $10$ volts.
$∴$ Current through $5 Ω$ , $I = \frac{10}{5} = 2 A$

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