In the circuit shown in the Figure charge on 1μF and 3μF capacitors respectively is
3μC,21μC
Current through any branch of resistors will be,
I=9V9Ω=1A
Potential drop across 1μF capacitor = 1×3=3V
Potential drop across 3μF capacitor = 1×7=7V
Charge on 1μF capacitor Q1=CV=1×3=3μC
Similarly charge on 3μF capacitor Q2=7×3=21μC