Question

In the circuit shown in the figure, identify the equivalent gate of the circuit and make its truth table.

Answer 1

$\begin{array}{ccccc}A& B& A^{\prime }& B^{\prime }& Y=\overline{A^{\prime }.B^{\prime }}\\ 0& 0& 1& 1& 0\\ 0& 1& 1& 0& 1\\ 1& 0& 0& 1& 1\\ 1& 1& 0& 0& 1\end{array}$

Thus, the equivalent gate is "OR" gate.