Question

In the circuit shown in the figure, if the potential at point $A$ is taken to be zero, the potential at point $B$ is

• A. $+1\text{V}$
• B. $-1\text{V}$
• C. $+2\text{V}$
• D. $-2\text{V}$
  

Answer 1

The correct option is A $+1\text{V}$

Current in $CD$ wire will be $1\text{A}$

Applying $KVL$ along $ACDB$ path:
$V_A+1+2\times 1-2=V_B$
$\Rightarrow 0+1+2-2=V_B$
$\therefore V_B=+1\text{V}$