Question

In the circuit shown in the figure potential difference between $A$ and $B$ is:

• A. 30V
• B. 60V
• C. 10V
• D. 90V

Answer 1

The correct option is C 10V

R.E.F. Image I

$\therefore$ change supplies $=190\times \frac{15}{19}(q=CV)$

$=150C$

$\because 1$ & $\frac{15}{4}$ are in scenes

so, both have same changes.

$\therefore \frac{1.5}{4}$ have $150C$.

$\therefore V=\frac{q}{c}=\frac{150}{\left(\frac{15}{v}\right)}=40V.$

$\therefore$ from diagram (1) :-

voltage across $1C,3C$ is $40V$

Ref. Image II

both have change = $C_{eq}$V

$=\frac{3}{4}\times 40=30C$

$\therefore V_{AB}=\frac{q}{3}=\frac{30}{3}=10V.$