In the circuit shown in the figure, the input voltage are VC=15V and VB=10V. The value of IB,IC and β respectively is (Assume that the collector and base voltages are negligible.)
A
0.05mA,7.5mA,150
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B
0.5A,7.5A,15
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C
50mA,750mA,150
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D
0.05mA,75mA,15
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Solution
The correct option is A0.05mA,7.5mA,150
For base side; VB−0=IB×200×103Ω10=IB×200×103ΩIB=10200×103=0.05mA
For collector side; VC−0=IC×2×103Ω 15−0=IC×2×103Ω⇒IC=152×103=7.5mA∴β=ICIB=7.50.05=7505=150