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Transistor as an Amplifier

In the circui...

Question

In the circuit shown in the figure, the input voltage $V_{i}$ is $20 V$ , $V_{B E} = 0 V$ and $V_{C E} = 0 V$ . The value of $I_{B}$ is given by

40 μ A

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25 μ A

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20 μ A

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40 μ A

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Solution

The correct option is D $40 μ A$
$V_{i} = I_{B} R_{B} + V_{B E} 20 = I_{B} \times (500 \times 10^{3}) + 0 I_{B} = \frac{20}{500 \times 10^{3}} = 40 μ A$

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