Question

In the circuit shown in the figure, the potential difference across the $4.5\mu F$ capacitor is:

• A. $\frac{8}{3}$ volt
• B. 4 volt
• C. 6 volt
• D. 8 volt

Answer 1

The correct option is D 8 volt

Total capacitance, $\frac{1}{C}=\frac{1}{4.5}+\frac{1}{9}=\frac{1}{3}$
or $C=3\mu F$
Charge, Q = CV = 3 $\mu$ F $\times$ 12V = 36 $\mu$ C
Potential difference across $4.5\mu F$ capacitor

$=\frac{36\mu C}{4.5\mu F}=8V$