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Question

In the circuit shown in the figure, the total charge is 750 μC and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is-


A
450 μC
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B
590 μC
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C
160 μC
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D
650 μC
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Solution

The correct option is B 590 μC

Using conservation of charge,

q1=q2+q3

750 μC=q2+q3 [C2 C3]

Charge on capacitor C3 is,

q3=C3×V3=8×20=160μC

q2=750μC160μC=590μC

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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