CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the circuit shown in the figure, the total charge is 750 μC and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is-


A
450 μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
590 μC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
160 μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
650 μC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 590 μC

Using conservation of charge,

q1=q2+q3

750 μC=q2+q3 [C2 C3]

Charge on capacitor C3 is,

q3=C3×V3=8×20=160μC

q2=750μC160μC=590μC

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

flag
Suggest Corrections
thumbs-up
42
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Circuit
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon