Question

In the circuit shown in the given figure, the resistances $R_1$ and $R_2$ are respectively.

• A. $14\Omega$ and $40\Omega$
• B. $40\Omega$ and $14\Omega$
• C. $40\Omega$ and $30\Omega$
• D. $14\Omega$ and $30\Omega$

Answer 1

The correct option is A

$14\Omega$ and $40\Omega$

$R_2=\frac{20V}{0.5A}=40\Omega =40\Omega$

Potential difference across $R_{1}69V–20V=49V$

Current in $R_1=0.5A+\frac{20}{10}+1A=3.5A$

$\therefore R_1=\frac{49}{3.5}=14\Omega$