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Question


In the circuit shown is figure, switch is closed then find the work done by battery till next steady state is achieved.

A
400 nJ
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B
600 nJ
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C
300 nJ
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D
200 nJ
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Solution

The correct option is A 400 nJ

Ceff=6×36+3=189=2ΔV across 6 nF=10 voltq=CeffΔVq=CeffΔV=6×10=2×10=60=20
Excess work done due to closing the switch is
W=ΔqV
=10(6020)=400 nC×JC=400 nJ

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