Question

In the circuit shown, $P\ne R$ and the reading of the galvanometer is same with switch S open or closed. Then

• A. $I_R=I_G$
• B. $I_P=I_G$
• C. $I_Q=I_G$
• D. $I_R=I_Q$

Answer 1

The correct option is A $I_R=I_G$

At the junction of resistance R and G,

If the current divides at the junction the current in the galvanometer would be

lower than the current in resistance R.

Now according to the question, as there is no deflection in the galvanometer

when the switch is closed,

This means there is no change in current on closing the switch.

i.e, current doesn't divide at the junction

Hence $I_R=I_G$

Option $\text{A}$ is correct answer.