In the circuit shown, reading of the voltmeter connected across 400Ω resistance is 30 V. If it is connected across 300Ω resistance then reading will be:
A
45V
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B
32.5V
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C
22.5V
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D
18V
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Solution
The correct option is C22.5V Current trough 400 Ω is I=30/400=3/40A As 400 Ω and 300 Ω are in series so same current I will pass through them. Voltage across 300 Ω is V′=300I=300(3/40)=22.5V