Question

In the circuit shown,
Table 1 Table - 2
(a) Potential difference across battery A (p) A
(b) Potential difference across battery B (q) B
(c) Power is supplied by battery (r) $14V$
(d) Power is consumed by battery (s) $9V$
(t) none

• A. a - p; b - p; c - q; d - r
• B. a - q; b - q; c - r; d - s
• C. a - r, b - t, c - p, d - q
• D. a - r; b - r; c - s; d - t

Answer 1

Answer: (C)

a - r, b - t, c - p, d - q

Current in the circuit $i=\frac{\text{net emf}}{\text{net resistance}}$

i.e. $=\frac{15-10}{3+1+1}$

$\therefore V_A=E-ir=15-\text{1X1}=14V$ (where r is the internal resistances of the battery)

$V_B=E+ir=10+\text{1X1}=11V$

Current is flowing out of the battery A. So Battery A is in discharging mode and power is supplied by the $\text{battery A}$

Current is entering in the battery B. So battery B is in charging mode that's why power is consumed by the $\text{battery B}$