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Byju's Answer

Standard XII

Physics

Inductors in Circuits

In the circui...

Question

In the circuit shown the capacitor is initially charged with a 12 V battery, when switch $S_{1}$ is open and switch $S_{2}$ is closed. $S_{1}$ is then closed and, at the same time, $S_{2}$ is opened. The maximum value of current in the circuit is:

1 μ A

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7.2 μ A

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720 μ A

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360 μ A

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Solution

The correct option is C $720 μ A$
$Q_{m a x} = 108 p C$
$\frac{1}{2} \frac{Q_{m a x}^{2}}{C} = \frac{1}{2} L i_{m a x}^{2}$
On solving
$i_{m a x} = 720 μ A$

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Similar questions

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In the circuit shown the capacitor is initially charged with a 12 V battery, when switch S1 is open and switch S2 is closed. S1 is then closed and, at the same time, S2 is opened. The maximum value of current in the circuit is:

The correct option is C 720μAQmax=108pC 12Q2maxC=12Li2max On solving imax=720μA

In the circuit shown the capacitor is initially charged with a 12 V battery, when switch $S_{1}$ is open and switch $S_{2}$ is closed. $S_{1}$ is then closed and, at the same time, $S_{2}$ is opened. The maximum value of current in the circuit is:

The correct option is C $720 μ A$
$Q_{m a x} = 108 p C$
$\frac{1}{2} \frac{Q_{m a x}^{2}}{C} = \frac{1}{2} L i_{m a x}^{2}$
On solving
$i_{m a x} = 720 μ A$