Question

In the circuit shown the cell has $emf=10V$ and internal resistance $=1\Omega$

• A. the current through the $3\Omega$ resistor is 1 A
• B. the current through the $3\Omega$ resistor is 0.5 A
• C. the current through the $4\Omega$ resistor is 0.5 A
• D. the current through the $4\Omega$ resistor is 0.25 A

Answer 1

Answer: (A), (D)

The correct options are
A the current through the $3\Omega$ resistor is 1 A
D the current through the $4\Omega$ resistor is 0.25 A

The equivalent resistance would be ,
$R=4+3+2+1$
$R=10ohms$
thus the current through the circuit would be
$I=\frac{E}{R}$
$I=1amp$
So current across 3 ohms will be $1A$.
Since the current will be divided symmetrically in both the branches,
In first branch it will be halved is $0.5A$
After that it will be halved again i.e. $0.25A$.
Thus the current across $4ohms$ would be $0.25A$