In the circuit shown, the cell is ideal, with emf = 15V. Each resistor is of 3Ω. The potential difference across the capacitor is :
A
0
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B
9V
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C
12V
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D
15V
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Solution
The correct option is C12V In the steady state capacitor is fully charged so no current will flow through resistor on most right resistor. By Kirchhoff's law for loop ABCEFA and CHGEC, we will get
3i1+3(i1+i2)=15⇒2i1+i2=5...(1) and 3i2+3i2−3i1=0⇒i1=2i2...(2) From (1) and (2), 5i2=5⇒i2=1 and i1=2 Thus potential across capacitor =3i2+3(i1+i2)=3+9=12V