The value of unknown resistor RA- 4 -B- 8 -C- 5 -D- 10 -

The correct option is A 4 ΩCurrent in 20 Ω resistor i_1 = 4020=2 A From Kirchhoffs junction law, ∴ current in R, i_2=8+2=10A In case of loop, using kirchhoff ...

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Standard XII

Physics

Parallel Combination of Cells

the value of ...

Question

In the circuit shown, the ideal voltmeter reading is $40 V$ . Find the value of unknown resistor $R$

4 Ω

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8 Ω

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5 Ω

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10 Ω

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Solution

The correct option is A $4 Ω$
Current in $20 Ω$ resistor
$i_{1} = \frac{40}{20} = 2 A$

From Kirchhoffs junction law,
$∴$ current in $R, i_{2} = 8 + 2 = 10 A$

In case of loop, using kirchhoffs voltage law
$- i_{2} R - i_{1} \times 10 + 100 - 40 = 0 \Rightarrow R = 4 Ω$

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In the circuit shown, the ideal voltmeter reading is 40 V. Find the value of unknown resistor R

The correct option is A 4 ΩCurrent in 20 Ω resistor i1=4020=2 A From Kirchhoffs junction law, ∴ current in R, i2=8+2=10A In case of loop, using kirchhoffs voltage law −i2R−i1×10+100−40=0⇒R=4 Ω

In the circuit shown, the ideal voltmeter reading is $40 V$ . Find the value of unknown resistor $R$

The correct option is A $4 Ω$
Current in $20 Ω$ resistor
$i_{1} = \frac{40}{20} = 2 A$

From Kirchhoffs junction law,
$∴$ current in $R, i_{2} = 8 + 2 = 10 A$

In case of loop, using kirchhoffs voltage law
$- i_{2} R - i_{1} \times 10 + 100 - 40 = 0 \Rightarrow R = 4 Ω$