In the circuit shown, the ideal voltmeter reading is 40 V. The value of unknown resistor R is

$4 Ω$

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$8 Ω$

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$5 Ω$

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$10 Ω$

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Solution

The correct option is A
$4 Ω$

Current in $20 Ω$ resistor $i_{1} = \frac{40}{20} = 2 A$ $∴$ current in R, $i_{2}$ = 8 + 2 = 10A

In case loop, we have – $i_{2} R - i_{1} \times 10 + 100 - 40 = 0 \Rightarrow R = 4 Ω$

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In the circuit shown, the ideal voltmeter reading is 40 V. The value of unknown resistor R is

The correct option is A 4 Ω Current in 20 Ω resistor i1=4020=2A ∴ current in R, i2 = 8 + 2 = 10A In case loop, we have –i2R−i1×10+100−40=0 ⇒ R=4Ω

The correct option is A
$4 Ω$

Current in $20 Ω$ resistor $i_{1} = \frac{40}{20} = 2 A$ $∴$ current in R, $i_{2}$ = 8 + 2 = 10A

In case loop, we have – $i_{2} R - i_{1} \times 10 + 100 - 40 = 0 \Rightarrow R = 4 Ω$