In the circuit shown, the resistances are given in ohms and the battery is assumed ideals with emf equal to 3.0 volts. The resistor that dissipated the most power is

R_{1}

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R_{2}

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R_{3}

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R_{4}

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Solution

The correct option is B $R_{1}$
As shown in circuit, $R_{1}$ is in series with battery and $R_{2}$ and $R_{3}$ are in parallel to each other and battery.
Hence, power will be dissipated more in $R_{1}$ since, the combined resistance of the resistors with different values is always less than the smallest value resistor. Further power is not evenly dissipated over the resistances.

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