In the circuit shown the value of current given by the battery will be :

1 A

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2 A

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1.5 A

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3 A

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Solution

The correct option is A $1 A$
Converting the given diagram into its equivalent circuit and calculating the equivalent resistance between AB will get.
In figure,
$R_{e q} = \frac{(7 + 1 + 10) (6)}{7 + 1 + 10 + 6} = \frac{108}{24} = 4.5 Ω$
The current in the circuit given by the battery is,
$I = \frac{V}{2 + R_{e q} + 8 + 0.5}$

$I = \frac{15}{2 + 4.5 + 8 + 0.5}$
$I = \frac{15}{15}$
$I = 1 A$

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Similar questions

1 A, 2 A

3 A

∣ ∣ ∣ ∣ ∣ \begin{matrix} (a + 1) (a + 2) & a + 2 & 1 (a + 2) (a + 3) & a + 3 & 1 (a + 3) (a + 4) & a + 4 & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣

R_{1} = R_{2} = R_{3} = 10 Ω

R_{1}

R_{2}

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