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LC Oscillation

In the circui...

Question

In the circuit shown, the value of current I in Ampere is (Write upto two digits after the decimal point)

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Solution

By carefully removing the redundant current paths, we get

$V_{A B} = 20 V$
$V_{B C} = 16 V$
16 = $2 I \times 4 \Rightarrow I = 2 A$

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