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Question

In the circuit shown the variable resistance is so adjusted that the ammeter reading is same in both the position 1 and 2 of the key. The reading of ammeter is 2A. If E=10V, then x is
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A
2Ω
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B
5Ω
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C
10Ω
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D
20Ω
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Solution

The correct option is B 5Ω
Since reading of ammeter is 2A, the current through wire 1 is 2A.
Same must be the current through wire 2.
Applying Kirchoff's Voltage Law through the loop containing both positions of key.
E(I)(x)=0
x=E2A=5Ω

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