In the circuit shown, the voltmeter reading is 40 V. Find the value of unknown resistor R

4 Ω

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8 Ω

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5 Ω

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10 Ω

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Solution

The correct option is A $4 Ω$
Current in $20 Ω$ resistor $i_{1} = \frac{40}{20} = 2 A$ $∴$ current in R, $i_{2} = 8 + 2 = 10 A$
In case loop, we have $- i_{2} R - i_{1} \times 10 + 100 - 40 = 0 \Rightarrow R = 4 Ω$

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In the circuit shown, the voltmeter reading is 40 V. Find the value of unknown resistor R

The correct option is A 4ΩCurrent in 20Ω resistor i1=4020=2A ∴ current in R, i2=8+2=10A In case loop, we have −i2R−i1×10+100−40=0⇒R=4Ω

The correct option is A $4 Ω$
Current in $20 Ω$ resistor $i_{1} = \frac{40}{20} = 2 A$ $∴$ current in R, $i_{2} = 8 + 2 = 10 A$
In case loop, we have $- i_{2} R - i_{1} \times 10 + 100 - 40 = 0 \Rightarrow R = 4 Ω$