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Question

In the circuit, the battery is ideal. A voltmeter of resistance 600Ωis connected in tum across R1 and R2. giving readings V1 and V2 respectively:

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A
V1=80V
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B
V1=60V
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C
V2=30V
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D
V2=40V
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Solution

The correct options are
B V2=30V
D V1=60V
When voltmeter is connected across [R1] ,the equivalent resistance of voltmeter's resistance and [R1] will be 300 ohm and potential drop will be same across [R1] and [R2] i.e. 60 volts.
When voltmeter is connected across [R2] ,the equivalent resistance of voltmeter's resistance and [R2] will be 200 ohm and potential drop across [R1] and [R2] will be in the ratio [3/1] ,which give [V2=30] volts.
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