Question

In the CO molecule, the centre of mass is at a distance of 0.068 nm from the carbon atom. The separation between the nuclei of carbon and oxygen is

• A. $\frac{28\times 0.068}{16}nm$
  
• B. $\frac{28\times 0.068}{12}nm$
• C. $\frac{16\times 0.068}{28}nm$
  
• D. $\frac{12\times 0.068}{28}nm$

Answer 1

The correct option is A $\frac{28\times 0.068}{16}nm$


Here $0.068nm=\frac{12\times 0+16\times x}{12+16}=\frac{16x}{28}$
Where x is the separation between the nuclei. Hence the correct choice is (a).