You visited us 1 times! Enjoying our articles? Unlock Full Access!

Percentage Composition

In the combus...

Question

In the combustion of $2 g$ of methane, $25 k c a l$ heat is liberated. Find the molar heat of combustion of methane.

100 k c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 k c a l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

75 k c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 k c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $200 k c a l$
Reaction: $C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$
Molar mass of $C H_{4} = 16 g$
We know, molar heat of combustion is the heat released when 1 mole of a substance is completely burned.
So, heat evolved by combustion of 2 g of $C H_{4} = 25 k c a l$
Heat evolved by $16 g$ of $C H_{4}$ = $\frac{25 \times 16}{2} = 200 k c a l$

Suggest Corrections

Similar questions

2 g

25 k c a l

The heat of combustion of methane is $- 880 k J m o l^{- 1}$ . The quantity of heat liberated in the combustion of $3.2 g$ methane is:

2 g

26575 C a l

C O_{2}

H_{2} O

- 97000

- 68000 C a l

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program