MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Carbon Monoxide

In the combus...

Question

In the combustion of methane, what is the limiting reactant and why?

Open in App

Solution

Methane is the limiting reactant because the other reactant is oxygen of the air which is always present in excess. Thus, the amount of $C O_{2}$ and $H_{2} O$ formed will depend upon the amount of $C H_{4}$ burnt.

Suggest Corrections

thumbs-up

1

Similar questions

Q. For the combustion of sucrose:

C_{12} H_{22} O_{11} + 12 O_{2} \to 12 C O_{2} + 11 H_{2} O

10.0 g of sucrose and 10.0 g of oxygen are made to react. Which of the following reactants will be the limiting reagent and what amount of the excess reactant will be left?

Q. The heat of combustion of methane is

- 800

kJ. What is the heat of combustion for

4 \times 10^{- 4}

Q. What wiII be the heat of formation of methane, if the heat of combustion of carbon is

^{'} - x^{'} k J

, heat of formation of water is

^{'} - y^{'} k J

and heat of combustion of methane is

^{'} z^{'} k J

?

Q. What will be the heat of formation of methane, if the heat of combustion of carbon is

- x k J

, heat of formation of water is

- y k J

and heat of combustion of methane is

z k J

?

10

g of methane is burnt in oxygen, the heat evolved is

560

kJ. What is the heat of combustion (in

{kJ mol}^{- 1})

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Carbon Monoxide

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Carbon Monoxide

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon