In the complex $[C o C l_{2} (e n)_{2}] B r$ , the co-ordination number and oxidation state of cobalt are:

6 and +3

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3 and +3

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4 and +2

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6 and +1

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Solution

The correct option is A 6 and +3
en is a bidentate ligand and $C l^{-}$ is a monodentate ligand.
Hence, coordination number is 6
. Oxidation state of Co:
x – 2 = +1
x = + 3

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