Question

In the complex ion $\left[Fe\right(EDTA){]}^{-}$ the coordination number and oxidation state of central metal ion is:

• A. C.N. $=6$ O.N. $=+3$
• B. C.N. $=1$ O.N. $=-1$
• C. C.N. $=4$ O.N. $=+2$
• D. C.N. $=3$ O.N. $=+3$

Answer 1

The correct option is A C.N. $=6$ O.N. $=+3$

In $\left[Fe\right(EDTA){]}^{-}$, the denticity of EDTA=6, so the co-ordination number $=6$.

The change of EDTA$=-4$

Let oxidation state of Fe is n.

$\Rightarrow n-4=-1$

$n=+3$

$\Rightarrow C.N=6;Oxidationnumber=+3$