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Question

In the complex ion [Fe(EDTA)] the coordination number and oxidation state of central metal ion is:

A
C.N. =6 O.N. =+3
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B
C.N. =1 O.N. =1
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C
C.N. =4 O.N. =+2
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D
C.N. =3 O.N. =+3
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Solution

The correct option is A C.N. =6 O.N. =+3
In [Fe(EDTA)], the denticity of EDTA=6, so the co-ordination number =6.

The change of EDTA=4

Let oxidation state of Fe is n.
n4=1

n=+3

C.N=6; Oxidation number=+3

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