In the complex numbers, where $i^{2} = - 1$ , what is the value of $5 + 6 i$ multiplied by $3 - 2 i$ ?

27

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27 i

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27 + 8 i

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15 + 8 i

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15 - 18 i

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Solution

The correct option is C $27 + 8 i$
We know, $i^{2} = - 1$
The required product is $(5 + 6 i) (3 - 2 i)$
$= 15 - 10 i + 18 i + 12$
$= 27 + 8 i$

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Similar questions

Δ = ∣ ∣ ∣ ∣ ∣ \begin{matrix} \sqrt{6} & 2 i & 3 + \sqrt{6} \sqrt{12} & \sqrt{3} + \sqrt{8 i} & 3 \sqrt{2} + \sqrt{6 i} \sqrt{18} & \sqrt{2} + \sqrt{12} i & \sqrt{27} + 2 i \end{matrix} ∣ ∣ ∣ ∣ ∣

Δ

x

y

\frac{x}{1 + 2 i} + \frac{y}{3 + 2 i} = \frac{5 + 6 i}{- 1 + 8 i}

x, y \in R

\frac{x}{1 + 2 i} + \frac{y}{3 + 2 i} = \frac{5 + 6 i}{8 i - 1}

Express the following in the form + ib where a, b Є R.

(\frac{6 + 8 i}{1 - 2 i})

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